Supposedly Trivial math question.

Steve Meyers steve at
Tue Oct 1 10:59:34 MDT 2013

On 10/1/13 10:45 AM, Levi Pearson wrote:
> What the problem*actually*  says is that the denominational system is
> strictly a place-value system of arbitrary base.  So all of the
> denominations will be powers of the base.  The example is in base-10,
> and specifically lists only powers of 10, not multiples of those
> powers.  So, no $20 bills, $0.25 bills, etc.

Okay, that makes sense.  I didn't get that from the original post, but 
that would definitely make the problem a lot easier.  You're basically 
just converting to whatever base you're using, and then using each digit 
as a number of bills for its place value.


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