Virtual COM port on Linux

Dave Smith dave at thesmithfam.org
Mon Mar 15 12:48:46 MDT 2010


Stuart Jansen wrote:
> Because echo is merely processing its argv and the '\0' is seen as
> terminating the arg, not part of the arg.

So the shell is parsing the $'\x' and turning it into a binary blob for 
echo? That makes sense.

--Dave



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