itoa'd you so?
smorrey at gmail.com
Fri Sep 21 16:16:33 MDT 2007
So does this presnet a real world bug, or would the user just perform
some bounds checking prior to handing it off to the function?
if(myval < 0 && abs(myval) == myval)
if(myval == INT_MIN)
On 9/21/07, Dave Smith <dave at thesmithfam.org> wrote:
> Levi Pearson wrote:
> > The answer lies in 2's complement binary representation of integers.
> > There aren't the same number of integers to the left and to the right
> > of 0; there's one more to the left. So, the absolute value of the
> > smallest representable integer isn't representable in the same number
> > of bits.
> Yup, so in other words abs(INT_MIN) returns INT_MIN because it wraps
> around. :)
> Nice work Levi, and a good explanation.
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