OO php: static and factory classes
jeff at zingstudios.com
Fri Aug 31 16:30:43 MDT 2007
> $objName = "Widgit";
> Why does the bottom one not work?
Because $objName is a string variable. You can't apply a method to a
You *may* be able to do this (I haven't tested it):
The double-dollar means "interpret the string", which might evaluate
to "Widgit" and work.
This will definitely work:
eval($objName . "::getWidgetStatic();");
Here you're sticking the string into the eval() expression, so it gets
intepreted like you want.
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