dave at thesmithfam.org
Sat Sep 23 15:48:45 MDT 2006
Levi Pearson wrote:
> On Sep 23, 2006, at 1:49 PM, Dave Smith wrote:
>> Wrong. In both cases (char* and char), the variable itself stores
>> the address. You do not need the & operator in either case.
>> In fact, using the & operator is incorrect, because it will give you
>> the address of the variable that was already holding the address of
>> the character array, instead of the address of the character array.
> No, you are wrong, at least partially. Both a char * and char
> variable will evaluate to an address, but in the case of char that
> address is both the address of the first element /and/ the address of
> the variable itself. With a char *, the address it is pointing to is
> not the same as its own address, so the & operator acts differently on
> char * than char.
At least we agree that the & operator is not needed to print the address
of a character array, which was the original poster's question.
More information about the PLUG