c++ question

[Steve]

In that case &foo would be &foo[0] it's implied

On 9/22/06, Russel Caldwell <caldr704 at gmail.com> wrote:
> Here's what's confusing me. If I create a integer array I will get the
> following:
>     int foo[10] = {1, 2, 3};
>
>     cout << &foo;      //gives me the address foo
>     cout << foo;        //gives me the address of of foo[0]
>
> If I create a character array:
>    char foo[] = "Hello";
>
>     cout << &foo;      //gives me the address of foo
>     cout << foo;        //gives me the string stored in foo
>     What will give me the address of foo[0]?
>
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