Doh! Stupid Programming Mistakes <humor>

[Jacob Fugal]

On 10/19/06, Steve <smorrey at gmail.com> wrote:
> So what's the total number assuming infinite "allowed" processes, that
> this stinker managed to spawn?

2^10

I don't think the post-increment matters. The first child will still
only spawn nine others. Example with i = 3:

  #include <stdio.h>
  int main (int argc, char *argv[])
  {
      int x;
      for(x=0; x<3; x++){ fork(); }
      printf("I am Spartacus!\n");
  }

output:

  I am Spartacus!
  I am Spartacus!
  I am Spartacus!
  I am Spartacus!
  I am Spartacus!
  I am Spartacus!
  I am Spartacus!
  I am Spartacus!

In every iteration, each process forks. So the number of processes
doubles each iteration. 3 iterations, 2^3=8 processes.

Jacob Fugal